At some point in the distant future we may want to work with Divided Power structures if I ever get around to crystalline cohomology, so why not start writing about it now? Basically this is how we are going to be able to talk about things that require division when working in positive characteristic. Today we’ll just quickly give the definition and then a bunch of easy examples.
Suppose is a commutative ring and
an ideal. Divided powers on
are a collection of maps
for all integers
for which we have the following five properties:
1. For all ,
,
and
2. For we have
3. For ,
, we have
4. For we have
, where
5. where
, the number of partitions of a set with
elements into
subsets with
each.
You may have noticed that these conditions seem to just be a formal encoding of the power map from characteristic
. You’d be wrong, but basically correct. A close examination of the fourth condition actually gives that the map must be
when dividing makes sense (i.e.
is a
-algebra).
We say is a P.D. ideal,
is a P.D. ring and
is a P.D. structure on
. Of course, P.D. stands for “Divided Power”. OK, not really, it stands for “Puissances Divisees” which is just french for divided powers. We may want to form this into a category, so we’ll say a P.D. morphism
is a ring map
with the property
and it commutes with the divided powers
for all
.
We already gave the -algebra example. In fact, in that case every ideal has that as its unique P.D. structure. For any ring,
together with
and
is a P.D. structure. The first interesting example is to let
be a DVR of unequal characteristic
with uniformizing parameter
. Recall that if
, then
is the absolute ramification index of
. We get that
has a P.D. structure if and only if
. In particular, if
is perfect, then since
is absolutely unramified
has a unique P.D. structure on it.
We can also define subobjects in the obvious way. If is a P.D. ideal, then another ideal
is a sub P.D. ideal if
for any
. In other words, the P.D. structure restricts to be a P.D. structure on the smaller ideal.
Let’s end with a nice little lemma for how find sub P.D. ideals. Suppose is a P.D. algebra,
a subset and
the ideal generated by
. We have that
is a sub P.D. ideal if and only if
for all
.
Here is the proof. By definition if it is a sub P.D. ideal, then . That direction is done. Now suppose
for all
. Let
be the subset of
of the
for which
for all
. By assumption and construction
. By definition of generation, if
is an ideal, then
and we are done. Choose
and fix
. Now
since
is an ideal. Thus
. Lastly, suppose
, then using
an ideal again
, so
. Thus
is an ideal which proves the lemma.
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